When $a \ne 0$, there are two solutions to (ax^2 + bx + c = 0) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
http://mathjax.josephjctang.com/
1 | grep theme.mathjax -rl --include=\*.{ejs,js} /home/cs/oss/hexo/themes/spfk |
<% if (page.mathjax){ %>
/hexo/public/js/MathJax.js 添加引入
1 | <script type="text/javascript" |
文章开头加入
1 | title: xxxx |
mathjax: true
引入目录