When a≠0, there are two solutions to (ax^2 + bx + c = 0) and they are
x=−b±√b2−4ac2a.
http://mathjax.josephjctang.com/
1 | grep theme.mathjax -rl --include=\*.{ejs,js} /home/cs/oss/hexo/themes/spfk |
<% if (page.mathjax){ %>
/hexo/public/js/MathJax.js 添加引入
1 | <script type="text/javascript" |
文章开头加入
1 | title: xxxx |
mathjax: true
引入目录
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